A Ladder of length 18m is placed against a wall such that it reaches the top of the wall. the height of the wall from the ground is 9√3 m. the angle formed by the ladder with the ground is..........?
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3
Answer:
The angle will be 60° as sin60° = √3/2
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2
Answer:
Length of ladder (Hypotenuse) = 18 m
Height of wall (Perpendicular) = 9√3 m
By Pythagoras theorem ⇒ Base^2 = Hypotenuse^2 - Perpendicular^2
⇒ Base^2 = (18)^2 - (9√3)^2
⇒ Base^2 = 324 - 243 = 81
⇒ Base = √81 = 9 m
The angle formed by the ladder with the ground is:
tan Ф = Perpendicular / Base = 9√3 / 9 = √3
tan 60° = √3
therefore, The angle formed by the ladder with the ground = 60°
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