Question

a ladder of length 29 ft is leaning against a wall of a building and is placed such that a foot ladder is 21ft from the base of the building .how far above the ground does the ladder touch the building .
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Answer 1

Answer:8 foot by calculating it's height far. By subtracting 29 - 21 foot

=> 8 foot

Step-by-step explanation:

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

a ladder of length 29 ft is leaning against a wall of a building and is placed such that a foot ladder is 21ft from the base of the building .how far above the ground does the ladder touch the building .

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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See figure in the picture above attached for better understanding:-

Now,from figure AB is the building ;AC is the length of the ladder of 29 ft which is lean against the wall of a building.

$\bold{To\:Find}$ :how far above the ground does the ladder touch the building .

=>Let BC be the distance of 'x'between the ground and ladder touch the ground

Now solving :-

By Pythagoras theorem:-

$\bold{= > {(AC)}^{2} = {(AB)}^{2} + {(BC)}^{2} }$

$= > {(29)}^{2} = {(21)}^{2} + {(x)}^{2}$

$= > 841 = 441 + {x}^{2}$

$= > 841 - 441 = {x}^{2}$

$= > 400 = {x}^{2}$

$= > {x}^{2} = 400$

$= > x = \sqrt{400} = 20$

Hence,Ladder the building from the ground at $\bold{\red{20 \:ft}}$

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