a ladder of length 5 m is placed against a 4 m long wall find the distance of the ladder from the foot of the wall
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Answer:
3 Metres
Step-by-step explanation:
According to the problem given ,
Length of the ladder = AC = 5m
Height of the wall = BC = 4cm
Distance between foot of the ladder
to foot of the wall = AB
In ∆ABC , <B = 90°
By Phythogarian theorem ,
AC² = AB² + BC²
=> AC² - BC² = AB²
=> AB² = AC² - BC²
= 5² - 4²
= 25 - 16
AB² = 9
AB = √9
=> AB = 3 m
Hope this helps! Refer to the diagram if you're confused.
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