a ladder of length 5m against a vertical wall with it's foot 1.8m away from the base of wall. How far up the wall does the ladder reach.
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Answer:
let the ladder be ac, wall ab and base be bc
ac = 5m
bc= 1.8m
ab = ?
by pythagoras theorem
(ac)² = (ab)² + (bc)²
(5)² = (ab)² + (1.8)²
25 = (ab)² + 3.24
25 - 3.24 = (ab)²
21.76 = (ab)²
ab = √21.76
ab = 4.66m
Step-by-step explanation:
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