Question

A ladder of length 6 m makes an angle of 30° with the floor while leaning against one wall of a room. If the foot

of the ladder is kept fixed on the floor and it is made to lean against the opposite wall of the room, it makes an

angle of 60° with the floor. Find the distance between the two walls of the room. [Use 3 1.732 = ]​

Answer 1

Answer:

8.196

PLEASE MARK AS BRAINLIST

Answer 2

Answer:

The total distance between the walls is  3(√3+1) meters.

Given :

Length of the ladder ,  L = 6m

angle made by the ladder with floor , if it rest on first wall , α= 30°

angle made by the ladder with floor , if it rest on Other wall , β= 60°

Step-by-step explanation:

Let the length of the wall = x meters

Distance between the first wall and foot of ladder = a meters

Distance between the second wall and foot of ladder = b meters

Ladder is standing against the first wall:

cos 30 = a/6

√3/2 = a/6

a= 3√3

Ladder is standing against the Second wall:

cos 60 = b/6

1/2 = b/6

b = 3

Total distance between the walls = a + b

= 3 + 3√3

=3(√3+1)

Hence the total distance between the walls is  3(√3+1) meters.