Question

a ladder of length 65m is resting against a wall.if it slips 8m down the wall then its bottom will move away from the wall by nm.if it was initially 25m away from it what is the value of x? solution

Answer 1

the length of the Wall after it slips is 39m away from wall

Answer 2

AC = 65m

AB=65-8=57m

BC= (25+x ) m

AC² = AB² + BC²    [ using pythagorus theorem]

(65)² = (57)² + ( 25+ x)²

4225 = 3249 + 625 + x²

x²= 4225 - 3874= 351

x = √351= 18.7 m

Ans:- the value of the 'x' will be 18.7m