a ladder of length 65m is resting against a wall.if it slips 8m down the wall then its bottom will move away from the wall by nm.if it was initially 25m away from it what is the value of x? solution
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the length of the Wall after it slips is 39m away from wall
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AC = 65m
AB=65-8=57m
BC= (25+x ) m
AC² = AB² + BC² [ using pythagorus theorem]
(65)² = (57)² + ( 25+ x)²
4225 = 3249 + 625 + x²
x²= 4225 - 3874= 351
x = √351= 18.7 m
Ans:- the value of the 'x' will be 18.7m
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