Question

A ladder resting against a vertical wall has its foot on the ground at a distance of 6ft from the wall. A man on the ground climbs 2/3 of the ladder, what is his distance from the wall?​

Answer 1

Answer:

Step-by-step explanation:

A man climb 2/3rd of the ladder:

_____________________________________________

→So, in △ADE & △ABC ,

→∠A=∠A (common) ,

→∠ADE=∠ABC (corresponding Angle) ,

→∠AED=∠ACB (corresponding Angle) ,

⇒△ADE∼△ABC.

→ AD/AB=DE/BC,

→3/5=DE/6,

→ DE=18/5,

$DE=3.6ft.$

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Answer 2

Step-by-step explanation:

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