Question

a lady has 25 p coin and 50 p coins if in all she has 80 coins totalling 25rs how many coins of each kind does she have ​

Answer 1

Answer:

Let the number of 20 paise coins be x and the 25 paise coins be y.

= > 20x + 25y = 1150. 

= > 4x + 5y = 230 ------ (1)

Given that she has 50 coins in total.

= > x + y = 50.   ----- (2)

On solving (1) & (2) * 4, we get

4x + 5y = 230

4x + 4y = 200

-----------------------

        y = 30

Substitute y = 30 in (2), we get

= > x + y = 50

= > x + 30 = 50

= > x = 20.

Therefore the number of 20 paise coins = 20.

Therefore the number of 25 paise coins = 30.

Hope this helps!