Question

A lady has 36 rs.90 paise in her bag and total number of coins were 180.if there are only two type of coins i.e of 10paisa and 25paise,then find the number of 25 paisa coins

Answer 1

your answer is in the attachment above

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Answer 2

Answer:

126

Step-by-step explanation:

A lady has 36 rs.90 paise in her bag

Re.1 = 100 paisa

Rs.36 = $36 \times 100 = 3600 paisa$

So, Lady has amount in her purse = 3600+90 = 3690 paise

There are only two type of coins i.e of 10paisa and 25paise

Let x be the number of coins of 10 paisa

So, value of x coins of 10 paisa = 10x

Let y be the number of coins of 25 paisa

So, value of y coins of 25 paisa = 25y

Total number of coins were 180.

So, $x+y=180$  ---A

Lady has amount in her purse is 3690 paise

So, $10x+25y = 3690$ --B

Plot teh lines A and B on the graph

$x+y=180$  -- Blue line

$10x+25y = 3690$ --Green Line

Intersection point will provide teh solution .

Intersection point = (54,126)

So,  the number of 10 paisa coins are 54 and  the number of 25 paisa coins are 126.

Hence  the number of 25 paisa coins are 126