Question

A lady has only 25 Paise and 50 Paise coins in her purse. If she has 47 coins totaling Rs. 16.25, find the
number of each kind of coins.​

Answer 1

Answer:

LET the number of 25 paisa coins be x and 50 paisa coins be y

so , 25x +50y = 1250 - - - - (1) ( convering values in paisa)

and x +y = 40. - - - - - (2)

so x = 40 - y 

PUTTING the value of x in equation (1)

so, 25(40 - y) + 50y = 1250

1000 - 25y + 50y = 1250

25y = 1250 -1000

25y = 250

y = 10

SO the number of coins 50 paisa is 10 now putting this value of y in eq (2)

x + y = 40

x + 10= 40

and x =30

So , 25 paise coins = (x) = 30

50 paise coins = (y) = 10

Answer 2

Let the number of 25 paise coins be x and 50 paise coins be y.

= > 25x + 50y = 1625.  

= > x + 2y = 65 ------ (1)

Given that she has 47 coins in total.

= > x + y = 47.   ----- (2)

On solving (1) & (2), we get

x + 2y = 65

x + y = 47

-----------------------

        y = 18

Substitute y = 18 in (2), we get

= > x + y = 50

= > x + 18 = 50

= > x = 32

Therefore the number of 25 paise coins = 32.

Therefore the number of 50 paise coins = 18.

Hope this helps!