A lady has three dresses of different colours, three purses of different colours and two different pairs of shoes. Two of the colours are black & white. She refuses to take her white purse with her black dress. How many dress-purse-shoe combinations could she have?
Answers
Given : A lady has three dresses of different colours, three purses of different colours and two different pairs of shoes . She refuses to take her white purse with her black dress
To find : How many dress-purse-shoe combinations could she have
Solution:
Different Color of dress = 3
Different color pf purses = 3
Different Color of Shoes = 2
Total possible combination = 3 * 3 * 2
= 18
Number of possible Combination when She take white purse with her black dress. = 1 * 1 * 2 = 2
Hence dress-purse-shoe possible combinations = 18 - 2 = 16
in 16 ways she can choose dress-purse-shoe combinations such that She never take her white purse with her black dress
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