Question

A lady went to the market with few one rupee notes and few 20 paise coins when she returned she had as many one rupees notes as she original I had 20 paise coins and vice versa she actually came back with about two third of what she had gone with how much would she spend in the market if number of 20 paise coins lies between 45 to 50

Answer 1

reword your question ..last line is not very clear ?

2/3(x+y/5)=y+x/5

7x=13y

Answer 2

Answer:

She spend in the market if number of 20 paise coins lies between 45 to 50 is Rs.100.8.      

Step-by-step explanation:

Given : A lady went to the market with few one rupee notes and few 20 paise coins when she returned she had as many one rupees notes as she original I had 20 paise coins and vice versa she actually came back with about two third of what she had gone with.

To find : How much would she spend in the market if number of 20 paise coins lies between 45 to 50?

Solution :

Let she has x coins of 1  rupees

and y coins of 20 paise,

The total amount she has initially = $(x+0.2y)$ rupees,

According to the question,

The number of 20 paise coins after shopping = x

The number of 1 rupee coins after shopping = y

The amount after shopping =$(0.2x+y)$  rupees,

The required equation form is,

$\frac{2}{3} \text{ of }( x + 0.2 y ) = ( 0.2 x + y )$

$\frac{2}{3}\times (x+0.2 y) = 0.2 x + y$

$2x + 0.4 y = 0.6 x + 3 y$

$1.4 x = 2.6 y$

$\frac{x}{y}=\frac{2.6}{1.4}=\frac{13}{7}$

If number of 20 paise coins lies between 45 to 50.

The possible value of y = 49,

So, x = 91

The initial amount is

$(x+0.2y)=91+9.8=100.8$

Therefore, She spend in the market if number of 20 paise coins lies between 45 to 50 is Rs.100.8.