Question

a lake is 10.33 meters deep. In which T=constant. In its base there is air bubble of radius 1 cm find the radius of the air bubble when it reaches the surface of lake
( answer only if it is geniune or else don't)​

Answer 1

Answer:

Given : P

1

=1.01×10

5

N/m

2

V

2

=V h=11 m ρ=1000 kg/m

3

Pressure at a depth h P

2

=P

1

+ρgh

∴ P

2

=1.01×10

5

+1000(10)(11)=2.11×10

5

N/m

2

Using P

1

V

1

=P

2

V

2

∴ 1.01×10

5

×V

1

= 2.11×10

5

×V

⟹V =2.089V