Physics, asked by pranaychandalia, 1 month ago

A lake is 5.0 m deep. The density of the water is 1000 kg / m3
.
(i) Calculate the pressure at the bottom of the lake due to this depth of water

Answers

Answered by dhyaniayush985
1

Explanation:

Correct option is

A

60000

Hydrostatic pressure = ϱgh

given  ϱ=103kg/m31g=10ms−2,h=6m

Pressure = 103m3kg×10s2m×6

                = 60000 Pa

Answered by ankitabareth200787
2

Answer:

Correct option is

A

60000

Hydrostatic pressure = ϱgh

given ϱ=10

3

kg/m

3

1g=10ms

−2

,h=6m

Pressure = 10

3

m

3

kg

×10

s

2

m

×6

= 60000 P

a

Explanation:

Correct option is

A

60000

Hydrostatic pressure = ϱgh

given ϱ=10

3

kg/m

3

1g=10ms

−2

,h=6m

Pressure = 10

3

m

3

kg

×10

s

2

m

×6

= 60000 P

a

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