A lake is 5.0 m deep. The density of the water is 1000 kg / m3
.
(i) Calculate the pressure at the bottom of the lake due to this depth of water
Answers
Answered by
1
Explanation:
Correct option is
A
60000
Hydrostatic pressure = ϱgh
given ϱ=103kg/m31g=10ms−2,h=6m
Pressure = 103m3kg×10s2m×6
= 60000 Pa
Answered by
2
Answer:
Correct option is
A
60000
Hydrostatic pressure = ϱgh
given ϱ=10
3
kg/m
3
1g=10ms
−2
,h=6m
Pressure = 10
3
m
3
kg
×10
s
2
m
×6
= 60000 P
a
Explanation:
Correct option is
A
60000
Hydrostatic pressure = ϱgh
given ϱ=10
3
kg/m
3
1g=10ms
−2
,h=6m
Pressure = 10
3
m
3
kg
×10
s
2
m
×6
= 60000 P
a
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