A lake near the Arctic Circle is covered by a 222-meter-thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 3 weeks, the sheet is only 1.251 point, 25 meters thick.Let y represent the ice sheet's thickness (in meters) after x weeks.
Answers
The question is a little incorrect, the ice sheet thickness should be 2m and not 222m.
Given: Initial thickness of the ice sheet = 2m
Thickness of ice sheet after three weeks = 1.25m
To Find: The function value
Solution:
Change in the thickness in 3 weeks = 2 - 1.25
= 0.75 meters,
Change in the thickness in 1 week = 0.75/3
= 0.25 meters,
As the ice melts with the constant rate. Thus,
Rate of ice decreasing = 0.25m per week.
Changes in t weeks = 0.25 t m
New thickness of ice after t weeks
= Initial thickness - Total changes in t weeks.
= S(t) = 2 - 0.25t
Answer: The required function for x and y is 2 - 0.25t
A lake near the Arctic Circle is covered by a 222-meter-thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 333weeks, the sheet is only 1.251.251, point, 25 meters thick.