Physics, asked by 28osho, 11 months ago

A lamp consume 50W and is lighted 2hrs daily for 31 days. How much unit of energy is consumed​

Answers

Answered by adityayadav06050
1

Explanation:

energy consumed = Power x time

50 w ----- 50/1000 kw

31 days x 2 hours = 62 hours

required energy = 1 /20 × 62 kWh

= 3.1 kwh

Answered by raushan6198
0

Explanation:

POWER =50W

TIME =2h

Energy consumed in 31 days

. = p× t × 32 day

= 50 × 2 ×31

= 3100 W

=3.1 KW (As 1000 W = 1KW)

= 3.1 Unit

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