A lamp consumes 1000J of electrical energy in 10s. What is its power
this lamp is used for 8 hours daily then calculate total energy con
the month of April
alculate total energy consumed for
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Answer:
24 kilowatt hour (kWh) or
864*10^5 J
Explanation:
In kWh
power is 1000 J per 10 sec
=100 J/sec
= 100 watt. (1J/sec = 1watt)
=0.1 kilowatt (kW)
Energy = Power * time
=0.1 kW * 8 hour * 30 days (in april)
=0.1 kW * 240 hour
=24 kWh
(In India 1 electricity unit = 1kWh)
In watt
power = 100 watt per sec
time in seconds
=30 days * 8 hrs * 3600 sec
=864000 sec
Energy = power * time
=100 J/s * 864000 s
=864 * 10^5 Joule
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