Physics, asked by rudranarnoli, 4 months ago

A lamp consumes 1500 J of electrical energy in 30 sec, what is its power?

Answers

Answered by ItzHeartlessBoy412
67

Answer:

Power = Work/Time

Work done= Energy consumed by the lamp = 1000 J

Time = 10 s

Power= 1000/10= 100 Js-1=100 W

Answered by nirman95
2

Given:

A lamp consumes 1500 J of electrical energy in 30 sec.

To find:

Power delivered by the lamp ?

Calculation:

Power is defined as the instantaneous rate of doing work.

In other words, power can be calculated from the ratio of work done and time taken to do the work.

  \rm\therefore \: power =  \dfrac{work}{time}

  \rm\implies \: power =  \dfrac{1500}{30}

  \rm\implies \: power =  50 \: watt

So, power delivered by the lamp is 50 watt.

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