a lamp consumes 500 J of electrical energy in 20 s . what is the power of the lamp . also find electrical energy consumed in units if the lamp operates for 2 hours daily for 15 days
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Power = energy / time
= 500/20 =25W
Energy consumed in 15 days
= 25 * (2 * 3600) / 15
= 2,700 KJ
or,
= 25 * 2 /* 15 = 750
= 0.750 kWH
= 500/20 =25W
Energy consumed in 15 days
= 25 * (2 * 3600) / 15
= 2,700 KJ
or,
= 25 * 2 /* 15 = 750
= 0.750 kWH
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