Question

A lamp has a power input of 5.0W. It wastes 1.0W of power heating the surroundings. What is the efficiency of the lamp?

give your answer in details

Answer 1

Answer:

$efficiency = \frac{power \: output}{power \: input} \times 100 \\ = \frac{4}{5} \times 100 \\ = 80\%$

other than power input and power output u can also use workd output and work input

power output = 5w-1w

Answer 2

The efficiency of the lamp is 80%. This means that only 80% of the power input is actually used to produce light, while the remaining 20% is wasted as heat.

Given:

Power input of the lamp = 5.0W

Power wasted in heating the surroundings = 1.0W

To find:

Efficiency of the lamp

Solution:

Efficiency of a device is defined as the ratio of the useful output energy or power to the input energy or power.

In this case, the useful output power is the power consumed by the lamp itself, which is the power input minus the power wasted in heating the surroundings.

Useful output power = Power input – Power wasted in heating the surroundings

Useful output power = 5.0W – 1.0W = 4.0W

Efficiency = Useful output power / Power input

Efficiency = 4.0W / 5.0W = 0.8 or 80%

Therefore, the efficiency of the lamp is 80%. This means that only 80% of the power input is actually used to produce light, while the remaining 20% is wasted as heat.

To learn more about watt from the given link.

https://brainly.in/question/20468631

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