A lamp in a moving train is at rest with respect to a passenger who is sitting in the train.
state true or false
Answers
Explanation:
When the coin was tossed the force acting on coin through frictional force stopped working and it starts moving with the uniform speed at which it was traveling at the time of toss, the distance covered by coin will be less compared to passenger and train as train is accelerating but coin is moving with same speed in horizontal direction.
Using kinematics equation S=ut+.5at
2
for calculating distance covered by train and coin:
S
train
=ut+.5at
2
;S
coin
=ut=>S
train
>S
coin
Where S
train
and S
coin
are distances covered by train and coin respectively ; a= train acceleration; u= velocity of train at time of toss; t= time taken to toss coin
CaseII,Train was decelerating:
When the coin was tossed the force acting on coin through frictional force stopped working and it keeps moving with uniform speed at which it was moving horizontally at time of toss, the distance covered by coin will be more compared to passenger and train as the train is decelerating but coin is moving with same speed in horizontal direction.
S
train
=ut−.5at
2
; S
coin
=ut=>S
train
<S
c
oin
CaseIII,Train was moving at uniform speed:
When the coin was tossed the force acting on coin through frictional force stopped working and it keeps moving with uniform speed at which it was moving horizontally at time of toss, the distance covered by coin will be same as of passenger and train.the correct answer is A.
S
train
=ut;S
coin
=ut=>S
train
=S
coin
Answer:
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