Physics, asked by balsldh1977, 1 day ago

A lamp is connected in series with a capacitor to a high frequency AC source. Then it is connected directly to the same source which is true statement about this. * 1 point (a) Lamp will glow more brightly when the capacitor is in series with it. (b) Lamp will glow more brightly on connecting it directly to the source. (c) Lamp glows with same brightness in both cases. (d) Brightness of glow of bulb does not depend upon capacitive reactance.​

Answers

Answered by vinayakanunni7
1

Answer:The lamp shines less brigthly

Explanation:The lamp shines less brightly because, when capacity of the capacitor is reduced, the capacitive reactance X

c

=

ωC

1

 increases. Hence, impedance Z increases resulting in decrease in current.  

The power for the resistor i

2

R  decreases, hence the lamp shines less brightly.

Answered by rajwinderbhatia1970
0

Answer:

option b

Explanation:

may be it will help you

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