Question

A lamp of 250 candle power is hanging at a distance of 6 m
from a wall. The illuminance at a point on the wall at a
minimum distance from lamp will be
(a) 9.64 lux (b) 4.69 lux
(c) 6.94 lux (d) None of these

Answer 1

Answer:

(d) None of these

Explanation:

1 Candle power = 0.981 Candela

Luminous intensity = 250*0.981 Candela

Minimum distance of lamp from wall = 6 m

Illuminance = L/$d^{2}$

= 250∗0.981/$6^{2}$

 = 6.8125 lux

Answer. D) none of these

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