A lamp of 50watt, 100 volt is to be connected with 200 volt, 50 Hz electric mains. Find capacitance of
citors to be connected in series with lamp.
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Answer:
9.19
Explanation:
Let the lamp has resistence = R
voltage drop in lamp = 100v
power = 50 w
P=V I
current I = P/V
= 50/100
=1/2 A
Capacitor connecter in series
P = V²/R , Volt = 200 v
R = 100²/50
= 200
For AC. V = 200 V
W = 50 Hz
I = V/Z
1/2 =200/√R² + xc² x c= capacitive resistence
x c = 1/2x wc
solving for c
1/2√R² + xc² = 200
1/2 = 200/√(100)² + 1/2 + 50 x c
we get C = 9.19 HF
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