A lamp of resistance 20 Ω and a conductor of resistance 8 Ω are
connected with a battery of 8 V in series. Calculate the :
(a) total resistance in the circuit
(b) current flowing through the circuit
Answers
Answered by
1
1. total resistance = 20+8
=28 ohms
2. As V=IR
8= I ·28
I=8/28
I=2/7
I=0.285 ampere
jainamshah8:
mark brainliest
Answered by
2
3.5amperes
28ohms. hope it helps you
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