A lamp of resistance 20 ohm is joined to a battery of 12 v . find the value of resistanceto be connected in series with the lamp in order to get current of 0.5 a
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GIVEN:
Lamp of resistance = 20 ohms
Current in circuit = 0.5A
Potential differences (volts) = 12 V
Therefore, As we know resistance is equal to voltage / current in amp
0.5 A = 12 V / (20 + r) ohms
12 V = (0.5 V) (20 + r)
12 = 10 + 0.5 r
12 - 10 = 0.5 r
2 = 0.5 r
r = 2 / 0.5
r = 20 / 5
r = 4 ohms
Lamp of resistance = 20 ohms
Current in circuit = 0.5A
Potential differences (volts) = 12 V
Therefore, As we know resistance is equal to voltage / current in amp
0.5 A = 12 V / (20 + r) ohms
12 V = (0.5 V) (20 + r)
12 = 10 + 0.5 r
12 - 10 = 0.5 r
2 = 0.5 r
r = 2 / 0.5
r = 20 / 5
r = 4 ohms
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