Question

A lamp rated 60w and an electric iron rated 800w are used for 6hrs everyday.Calculate total energy consumed in 30 days. Find the cost if the rate is 5.10 per Kwh.
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Answer 1

Explanation:

P1 = 60 W P2 = 800 W

E1 = 60 x 6 E2 = 800 x 6 = 4800 watt - hr

= 360 watt-hr.

Total energy consumed E = E1 + E2

= 360 + 4800

= 5160 watt-hour

Energy consumed in 30 days = 5160 x 30

= 154800 watt-hour

= 154.8 kWh.

Answer 2

Answer:

The answer will be 154.8 KWhr .