Question

A lamp rated 60w and an electric iron rated 800w are used for 6 hrs everyday calculate the total energy consumed in 30days

Answer 1

Ans:- total power consumed in watt is 60+800= 860 watt
Work in a day for 6 hours
Total energy consumed in 1 day = 860* 6= 5160wh
Convert in kwh
5160/1000= 5.16kwh
Energy consumed for 30 days = 5.16*30= [154.8] ans

Answer 2

Given:

• Rating of lamp = 60 watt
• Rating of iron = 800 watt
• They are used daily for 6 hours

To find:

Net energy used in 30 days ?

Calculation:

First of all, the net power used by the two devices are :

$P = 60 + 800 = 860 \: watt$

$\implies P = \dfrac{ 860}{1000} \:kilo watt$

$\implies P = 0.86 \:kilo watt$

Now, net energy in a day :

$\implies E = P \times t$

$\implies E = 0.86 \times6$

$\implies E = 5.16 \: kw \: hr$

Now, net energy in 30 days :

$\implies E_{net} = 5.16 \times 30$

$\implies E_{net} = 154.8 \: kw \: hr$

So, 154.8 kW hr energy is used by the two devices in 30 days.