Math, asked by adityamishra6370, 9 months ago

A land is brought on Rs 20000,then he sold 2/5part of it on 10percent gain 1/10 percent of reaming on 10percent loss in he how many percent he sell to get 20%on the whole transaction

Answers

Answered by CookCK
0

Answer:

he needs to sell remaing land at 30.74% profit to get net 20% profit at the end of whole transaction.

Step-by-step explanation:

Let's say he bought 'x' amount of land for 20,000.

Now he needs 20% profit on whole transaction which is 20*20000/100 = 4000. i.e. his total should be 24000 at the end.

1: he sold 2/5th part at 10% profit

2/5 of whole land = 2/5 * x

price of this part of land = 2/5 * 20000 = 8000

he got 10% gain on this part, thus total amount he received = 8000 + 10% of 8000 = 8800........ (1)

remaining land = x - 2/5 x = 3/5 * x

2: he sold 10% of remaining land at 10% loss

10% of remaining land = 3/5 * 1/10 = 3/50

price of this part of land = 3/50 * 20000 = 1200

he got 10% loss on this part, thus total amount he received = 1200 - 10% of 1200 = 1080........ (2)

remaining land = 90% of 3/5 = 27 / 50 x

price of remaining land = 20000 * 27/50 = 10800.

total money earned till now = 8800 + 1080 = 9880..... (1 + 2)

3: he needs 24000 at the end and he has 9880 now thus he will need to sell pending land at 24000 - 9880 = 14,120, which is (14120 - 10800) /10800 * 100 = 30.74% profit to gain 20% profit on whole transaction

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