A land is in the shape of rhombus the perimeter of the land is 160 m and the diagonal is 42 find the area of a land
Answers
Answer:
the area of rhombus is 1536m².
Step-by-step explanation:
Length of one side of a rhombus = 160/4 = 40 m
the length of other diagonal2= 40²-24² (48/2=24)
= 1600 - 576
=1024m²
=32
=32*2 = 64m
area of rhombus =48*64/2
=1536m²
∴the area of rhombus is 1536m².
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Answer:
Let the side of the rhombus be x m
perimeter= 4x
4x= 160m
x= 40m
Side of the rhombus is 40 m.
For area...
Step-by-step explanation:
Draw rhombus as given in the attached
Here side AB= 14 m
AC= 42m
AO= 21m
By pythagoras theorem in right triangleAOB
(AB)^2 = (AO)^2 + (OB)^2
(14)^2 = ( 21)^2 + (OB)2
196 = 441 +(OB)^2
(OB)^2 = 441 - 196
(OB)2 = 245
(OB) = 15.6 (approx)Now area of triangle ABD
1/2× BD × AO
1/2 × 15.6 ×2 × 21
15.6 × 21
327.6 m^2
Area of triangle BDC
327.6 m^2
Area of whole rhombus
2× 327.6
655.2 m^2(approx)
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