Math, asked by jitendrapalchirag480, 11 months ago

A lane 150 m by 10 m is to be paved with bricks of length 25 cm by 15 cm . find the cost of bricks required at the rate of Rs800 per thousand.​

Answers

Answered by Anonymous
2

\huge\bold\red{HOLA}

Hello,

we indicate with L length of the lane, with l breadth of the lane.

we calculate the area of a lane:

A₁=L×l=180×5=900 m²

we indicate with b length of the brick , with h breadth of the brick.

we calculate the area of a brick:

A₂=b×h=20×15=300 cm²

we convert the cm² in m² (1m²=10000 cm²)

300 cm²=0,03 m²

then

A₂=0,03 m²

we calculate the required number of bricks:

n=A₁/A₂=900/0,03=30000 bricks

we calculate the total cost of  bricks:

tot=(750×30000):1000=22500

plzz mark me as Brainliest ✌

Answered by mkarn4286
0

Answer:

Step-by-step explanation:

we indicate with L length of the lane, with l breadth of the lane.

we calculate the area of a lane:

A₁=L×l=180×5=900 m²

we indicate with b length of the brick , with h breadth of the brick.

we calculate the area of a brick:

A₂=b×h=20×15=300 cm²

we convert the cm² in m² (1m²=10000 cm²)

300 cm²=0,03 m²

then

A₂=0,03 m²

we calculate the required number of bricks:

n=A₁/A₂=900/0,03=30000 bricks

we calculate the total cost of  bricks:

tot=(750×30000):1000=22500

Read more on Brainly.in - https://brainly.in/question/15330640#readmore

Similar questions