A lane, 150 m long and 9 m wide, is to be paved with bricks, each measuring 22.5 cm by 7.5 cm. Find the number of bricks required.
Answers
Answer:
The of lane=l×b
of lane=l×b=150×9
of lane=l×b=150×9=1350m^2
of lane=l×b=150×9=1350m^2=13500000cm^2
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick=13500000/168.75
of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick=13500000/168.75=80000 no. of bricks will require
Area of lane = l*b= 150*9=1350m²
area of brick=22.5*7.5=168.75cm²=0.016875m²
number of bricks required=area of lane / area of brick
=1350/0.016875m²
=8000 bricks
so, 8000 bricks are required
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