Math, asked by DevCh1, 11 months ago

A lane, 150 m long and 9 m wide, is to be paved with bricks, each measuring 22.5 cm by 7.5 cm. Find the number of bricks required.

Answers

Answered by karanbagnaik
1

Answer:

The of lane=l×b

of lane=l×b=150×9

of lane=l×b=150×9=1350m^2

of lane=l×b=150×9=1350m^2=13500000cm^2

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick=13500000/168.75

of lane=l×b=150×9=1350m^2=13500000cm^2area of brick=l×b=22.5×7.5=168.75cm^2no. of bricks required=area of lane/area of brick=13500000/168.75=80000 no. of bricks will require

Answered by Anonymous
6

Area of lane = l*b= 150*9=1350m²

area of brick=22.5*7.5=168.75cm²=0.016875m²

number of bricks required=area of lane / area of brick

=1350/0.016875m²

                                        =8000 bricks

        so, 8000 bricks are required

✌✌✌✌✌

Similar questions