A lane,150m long and 9 m wide ,is it to be paved with brick ,each measuring 22.5 cm by 7.5cm .Find the number of brick required???
Answers
Answered by
5
150m=15000cm
9m=900cm
Thus,(15000*900)/(22.5*7.5)
=13500000/168.75
=80000
9m=900cm
Thus,(15000*900)/(22.5*7.5)
=13500000/168.75
=80000
Answered by
2
hello frnd!!!
here's ur answer...
given:
length of the lane=150m
breadth of the lane=9m
therefore are of the lane=l×b
=150×9
=1350m²
=135000cm²
length of the brick=22.5cm
breadth of the brick=7.5cm
area of the brick=l×b
=22.5×7.5
=168.75cm²
no. of bricks required to pave the lane=135000/168.75
=800
hence, 800brickes are required.
hope this helps...
☺☺☺
and all the best for Ur exam
here's ur answer...
given:
length of the lane=150m
breadth of the lane=9m
therefore are of the lane=l×b
=150×9
=1350m²
=135000cm²
length of the brick=22.5cm
breadth of the brick=7.5cm
area of the brick=l×b
=22.5×7.5
=168.75cm²
no. of bricks required to pave the lane=135000/168.75
=800
hence, 800brickes are required.
hope this helps...
☺☺☺
and all the best for Ur exam
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