Question

A lane 180 long and 5 M wide to be paved with bricks of length 20 cm and breadth 15 cm find the cost of the bricks that are required rupees 750 per thousand

Answer 1

hiii!!!

here's ur answer..

given the length of the lane = 180m

breadth of the lane = 5m

area of the lane = l × b

= 180 × 5

= 900m²

given the Length of the brick = 20cm = 0.2m

breadth of the brick = 15cm = 0.15m

area of the brick = l × b

= 0.2 × 0.15

= 0.03m²

therefore, total no. of bricks required to pave the lane = 900/0.03

= 30000 bricks are required.

now,

cost of 1000 bricks is = ₹750

cost of 1 brick = 750/1000

= ₹0.75

hence, total cost of paving the lane = 0.75 × 30000

= ₹22,500

hope this helps..!!