Question

A lane 180m long and 5m wide is to be paved with bricks of length 20cm and breadth 15 cm find the cost of the bricks that are required at the rate of 750 per thousand

Answer 1

Area of lane=area of rectangle
=180x5=900m²
Area of brick=0.2x0. 15
=0.03m²
No of bricks needed=900/0.03
=30000
Cost of bricks=30000/1000x750
=30x750=22500

Answer 2

The cost of the bricks that are required at the rate of 750 per thousand is Rs.22500

Step-by-step explanation:

Length of lane = 180 m

Width of lane = 5 m

Area of lane =$Length \times width= 180 \times 5 = 900 m^2$

Length of brick = 20 cm = 0.20 m

Breadth of brick = 15 cm = 0.15 m

Area of brick = $0.20 \times 0.15 = 0.03m^2$

No. of bricks required = $\frac{900}{0.03}=30000$

Cost of 1000 bricks = 750

Cost of 1 brick = 750/1000

Cost of 30000 bricks = $\frac{750}{1000} \times 30000=22500$

Hence the cost of the bricks that are required at the rate of 750 per thousand is Rs.22500

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A lane 180m long and 5m wide is to be paved with bricks of length 20cm and breadth 15 cm find the cost of the bricks that are required at the rate of 750 per thousand

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