Question

A lane 180m long and 5m wide is to be paved with bricks of length 20cm and bredth 15cm.find the cost of bricks that are required at a rate of rupees
750 per thousand

Answer 1

Answer:

Step-by-step explanation:

Surface area of the lane = length X width

    S₁ = 180 m * 5 m = 900 m²

Surface area of a brick = length X breadth

    S₂ = 20 cm * 15 cm 

         = 0.20 m * 0.15 m

         = 0.030 m²

Number of bricks required to pave the lane

  = Area of lane / Area of a brick

  = S₁ / S₂

  = 900 m² / 0.03 m²

  = 30, 000

Cost of bricks

 = cost of a thousand * number of thousands of bricks

 = Rs 750 * 30,000/1000

 = Rs 22, 500

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