Question

A lane 180m long and 5m wide is to be paved with bricks of length 20cm and breadth 15cm. Find the cost of bricks that are required at the rate of ₹ 750

Answer 1

Hello,

we indicate with L length of the lane, with l breadth of the lane.

we calculate the area of ​​a lane:

A₁=L×l=180×5=900 m²

we indicate with b length of the brick , with h breadth of the brick.

we calculate the area of a brick:

A₂=b×h=20×15=300 cm²

we convert the cm² in m² (1m²=10000 cm²)

300 cm²=0,03 m²

then

A₂=0,03 m²

we calculate the required number of bricks:

n=A₁/A₂=900/0,03=30000 bricks

we calculate the total cost of bricks:

tot=(750×30000):1000=22500

Hope it helps you pls mark as brainliest

Answer 2

Answer:

Step-by-step explanation:

Length of brick=0.20m

Breadth of brick=0.15m

Area of lane=180x5=900m^2

Area of brick=0.20x0.15=0.03m^2

Number of bricks=900÷0.03=30000

Total cost of bricks=30000x750=

Rupees22500000

Hope it helps you....

Please mark it as brainliest