A lane 180m long and 5m wide is to be paved with bricks, of L ength 20cm and breadth 15cm. Find the cost of the bricks that are required ,at the rate of Rupees 750per thousand
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length=180m=18000cm
breath=5m=500cm
area= 18000 * 500 = 9000000cm²
l*b(of brick)=15*20=300cm²
no of bricks=9000000/300 = 30,000 bricks
cost = 30000/1000*750 = ₹22,500
tanishk9812311777:
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Here lane forms rectangle.
Area of lane is l*b i.e., 180*5 i.e, 900m²
No.of bricks required are (900m²/20*15cm²)
900m²/3m²( Here cm² are concerted into m² in denominator)
Hence total of 300 bricks are required.
It costs 750 for 1000 bricks
then for 300 bricks it costs (300/1000)*750 i.e., 225/-
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