Question

A lane 6m wide and 120m long paved with bricks of size 20cm ×12 cm. What is the cost of pavement, if the brick cost Rs 2400 per thousand

Answer 1

Answer:

Area of lane = 6x120=720

= 720oooocm2

Area of one tile=20x12=240cm2

tiles required=720oooo / 240 =

3oooo tiles

Cost of Pavement =

3oooox2500/1000 = Rs 75000

Answer 2

Answer:

total area of road =length×breadth

Step-by-step explanation:

=120×6 metres

=720 metres.

total bricks=(area of lane)÷(area of one brick)

=(720)÷(0.2×0.12).

=(720)÷(0.024).

=30000.

total cost of pavement=no. of bricks × cost of one brick.

=30000×2400÷1000.

=72000 ₹