Math, asked by abhinavkumarforcode, 10 months ago

A language class has only 3 students A,B and C and they independently attend the class. The probabilities of the attendance of A, B and C on a given day are 1/2, 1/3 and 3/4 respectively. Find the probability that the total number of attendance in 2 consecutive days is exactly 3.

Answers

Answered by amitnrw
6

Given :  A language class has only 3 students . he probabilities of the attendance of A, B and C on a given day are 1/2, 1/3 and 3/4 respectively.

To find : probability that the total number of attendance in 2 consecutive days is exactly 3.

Solution:

total number of attendance in 2 consecutive days is exactly 3.

This can happen as below

1st day  - 0     2nd day 3

1st day    1     2nd  day  2

1st Day   2      2nd Day  1

1st day   3      2nd day   0

1st day  - 0     2nd day 3    

= (1 - 1/2)(1 - 1/3)(1 - 3/4)  (1/2)(1/3)(3/4)

=  (1/2)(2/3)(1/4) (1/8)

= 1/96

1st day   3      2nd day   0 will be same  = 1/96

1st day    1     2nd  day  2

1st day    1   =  (1/2)(1 - 1/3)(1 - 3/4)   + (1/3)(1 - 1/2)(1 - 3/4)  + (3/4)( 1 - 1/2)(1 - 1/3)

= (1/2)(2/3)(1/4)   + (1/3)(1/2)(1/4)  + (3/4)(1/2)(2/3)

=1/12  + 1/24  + 1/4

= 9/24

= 3/8

2nd  day  2       (1/2)(1/3)(1 - 3/4)  + (1/2)(1 - 1/3)(3/4)  + (1 - 1/2)(1/3)(3/4)

= (1/2)(1/3)(1/4)  + (1/2)(2/3)(3/4)  + (1/2)(1/3)(3/4)

= 1/24  + 1/4 + 1/8

= 10/24

= 5/12

1st day    1     2nd  day  2  =  (3/8)(5/12)  = 15/96

1st Day   2      2nd Day  1 will be same = 15/96

probability that the total number of attendance in 2 consecutive days is exactly 3. =

2 ( 1/96  + 15/96)

= 2 ( 16/96)

= 32/96

= 1/3

1/3 is the probability that  total number of attendance in 2 consecutive days is exactly 3.

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