Math, asked by radhikagarg1014, 2 months ago

A laptop was sold at a profit of 15%. If it was sold at
a price that was 10% lower, the profit would have
been Rs.1050. What is the cost price of the laptop?
(A) 321000
(B) 35000
(C) 230000
(D) 42000​

Answers

Answered by george0096
6

Answer:

  • Cost Price of the laptop is ₹ 30000.

Step-by-step explanation:

Given that:

  • A laptop was sold at a profit of 15%.
  • If the laptop was sold at a price that was 10% lower, the profit would have been ₹ 1050.

To Find:

  • Cost price of the laptop.

Let us assume:

  • The cost price of the laptop be x.

Finding selling price at a profit of 15% :

\rm{\longmapsto x+(15\%\;of\;x)}

Solving the bracket,

\rm{\longmapsto x+\bigg(\dfrac{15}{100}\times x\bigg)}

\rm{\longmapsto x+\bigg(\dfrac{15x}{100}\bigg)}

Opening the bracket,

\rm{\longmapsto x+\dfrac{15x}{100}}

Adding the numbers,

\rm{\longmapsto \dfrac{100x+15x}{100}}

\rm{\longmapsto \dfrac{115x}{100}}

Reducing the numbers,

\rm{\longmapsto \dfrac{23x}{20}}

Finding selling price 10% lower than the profit of 15% :

\rm{\longmapsto \dfrac{23x}{20}-\bigg(10\%\;of \;\dfrac{23x}{20}\bigg)}

Solving the bracket,

\rm{\longmapsto \dfrac{23x}{20}-\bigg(\dfrac{10}{100}\times\dfrac{23x}{20}\bigg)}

Cutting off the zeros,

\rm{\longmapsto \dfrac{23x}{20}-\bigg(\dfrac{1\!\!\!\not{0}}{100}\times\dfrac{23x}{2\!\!\!\not{0}}\bigg)}

\rm{\longmapsto \dfrac{23x}{20}-\bigg(\dfrac{1}{100}\times\dfrac{23x}{2}\bigg)}

Multiplying the numbers,

\rm{\longmapsto \dfrac{23x}{20}-\bigg(\dfrac{23x}{200}\bigg)}

Opening the bracket,

\rm{\longmapsto \dfrac{23x}{20}-\dfrac{23x}{200}}

Subtracting the numbers,

\rm{\longmapsto\dfrac{230x-23x}{200}}

\rm{\longmapsto \dfrac{207x}{200}}

According to the question:

\rm{\longmapsto \dfrac{207x}{200}-x=1050}

Subtracting the numbers,

\rm{\longmapsto \dfrac{207x-200x}{200}=1050}

\rm{\longmapsto \dfrac{7x}{200}=1050}

Transposing 200 from LHS to RHS and changing its sign,

\rm{\longmapsto 7x=1050\times200}

Multiplying the numbers,

\rm{\longmapsto 7x=210000}

Transposing 7 from LHS to RHS and changing its sign,

\rm{\longmapsto x=\dfrac{210000}{7}}

Dividing the numbers,

\rm{\longmapsto x=30000}

Hence, cost price of the laptop is ₹ 30000.

Answered by jainjainpriyank
0

Answer:

30000

Step-by-step explanation:

Let Consider

C.P.= 100

if profit is 15%

then S.P.=115

According to question if price lowered by 10%

then new S.P. =103.5 (10% of 115=11.5; 115-11.5)

So new profit = Rs 3.5  (S.P-C.P=>103.50-100=3.50)

But in question we have given real profit is 1050

So if 3.5=1050

1=300

and we consider C.P.=100

Real C.P.= 300×100=30,000

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