Question

A large ball 2 m in radius is made up of
a rope of square cross section with edge
length 4 mm. Neglecting the air gaps in
the ball, what is the total length of the
rope to the nearest order of magnitude?
Ans 106 m = 103km]​

Answer 1

Answer:

Your solution is in the attachment

Answer 2

Answer .......Volume of ball=Volume enclosed by rope.

4/3 π(radius)³ = Area of cross-section of rope ×length of rope.

∴ length of rope l=4/3 πr³ /A

Given : r=2 m and Area=A=4×4=16 mm² =16×10¯⁶ m²

∴ l=4×3.142×2³/3×16×10¯⁶ =3.142×2/3×10⁶ m ≈2×10⁶m.

∴ Total length of rope to the nearest order of magnitude=10⁶ m=10³ km

ANS. Total length of rope to the nearest order of magnitude=10⁶ m=10³ km

Explanation:

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