Question

A large ball 2m in radius is made up of arope of square cross section with edge length 4mm.Neglecting the air gaps in the ball,what is the total length of the ropeto the nearest order of magnitude?​

Answer 1

Answer:

The total length of the rope is 2094 km

Explanation:

Radius of the ball r = 2m

Cross sectional area of the rope = 4 × 4 = 16 mm² = 16 × 10⁻⁶ m²

Volume of the spherical ball

Using $\boxed{V=\frac{4}{3}\pi r^3}$

$\implies V=\frac{4}{3}\pi\times 2^3=33.51 \text{ m}^3$

Let the length of the rope is L

Then total volume of the rope = Volume of the ball

Volume of the rope = Area of cross-section × Length of the rope

Therefore

$16\times 10^{-6}\times L=33.51$

$\implies L=\frac{33.51}{16\times 10^{-6}} =2.0943 \times 10^6=2094.3\times 10^3 \text{ m}$

or, L = 2094.3 km ≈ 2094 km

Answer 2

Answer:

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Explanation:

answer is given there