A large balloon contains 11.7 grams of Helium. What volume will the helium occupy at an altitude of 10,000.meters, where the atmospheric pressure is 0.262 atm and the temperature is -50.0 °C? *
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Given A large balloon contains 11.7 grams of Helium. What volume will the helium occupy at an altitude of 10,000 meters, where the atmospheric pressure is 0.262 atm and the temperature is -50.0
- The molar mass of a substance is the number of grams per mole of that substance.
- So we have
- Atmospheric pressure P = 0.262 atm
- M = 4.0026 g/mol (since 10000 m moles helium = 4.0026 g/mol)
- T = - 50 + 273
- = 223 K
- Mass m = 11.7 g
- Universal gas constant R = 0.08206 L-atm / mol-K
- Now we have the equation V = mRT / PM
- = 11.7 g x 0.08206 L-atm / mol / K / 0.262 atm x 4.0026 g/mol
- V = 204.16
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https://brainly.in/question/18282136
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