Question

. A large block of ice has a cavity in it. A copper coin
of mass 20 gm (specific heat of copper =0.1
cal/gm/Cº) is heated to 200°C and then dropped in
to the cavity. If latent heat of ice is 80 cal/gm, the
mass of ice that melts is
1) 0.5 gm 2) 5 gm 3) 50 gm 4) 2.5 gm​

Answer 1

answer : option (2) 5gm

It is given that a large block of ice has cavity in it. a copper coin of mass 20g is heated to 200°C and then dropped in to the cavity.

we have to find the ice that melts.

heat lost by copper coin, H = ms∆T

= 20g × 0.1 cal/g/°C × (200°C - 0°C)

= 400 cal

heat gained by ice , Q = mLf

= m × 80 cal/g

here, heat lost by copper coin = heat gained by ice

⇒400 cal = 80 m cal/g

⇒m = 5 g

therefore mass of ice that melts is 5 g

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