Question

A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4 kg, collides with a smaller box with a mass of 2 kg that is stationary. The boxes stick together. What is the velocity of the two combined masses after collision.

Answer 1

Answer:

For larger box

Mass of large box (m¹) = 4kg

Initial Velocity of the large box (v¹) = 12m/s

For smaller box

Mass of small box (m²) = 2kg

Initial Velocity (v²) = 0m/s (At rest)

To Find:-

The Velocity of two combined masses after Collision.

Formulae used:-

Conservation of momentum

Accordung to Conservation of momentum total Momentum of system is conserved.

→ m¹u¹ + m²u² = m¹v¹ + m²v²

Now,

→ m¹u¹ + m²u² = m¹v¹ + m²v²

Atq.

→ m¹u¹ + m²u² = (m¹ + m²)v

→ (4)(12) + (2)(0) = (4 + 2)v

→ 48 + 0 = 6v

→ 48 = 6v

→ v = 48/6

→ v = 8m/s

Hence, The Velocity of the two combined masses after Collision is 8m/s.

HOPE IT HELPS