Question

A large can of milk contains 18 1/3 liters of milk. If the entire milk to be poured into smaller containers, each of capacity 1 5/(6 ) liters, then find the number of containers required pls answer fast

Answer 1

Answer:

Given,

The large can of milk contains 10⅓ litres of milk.

The capacity of one smaller container is 1 10/21 litres.

To find,

The number of required smaller containers to equally pour the entire milk of the larger container.

Solution,

The volume capacity of the bigger container = 10⅓ litres = 31/3 litres

The volume capacity of the smaller containers = 1 10/21 litres = 31/21 litres

Now,we have to calculate the number of nursery smallest continent by using the following mathematical formula,

Number of required smaller containers = volume capacity of the bigger container/volume capacity of one smaller container= 31/3 ÷ 31/21 = 31/3 × 21/31 = 7

Hence,7 smaller containers are required.

Step-by-step explanation:

IF YOU

Answer 2

10

Step-by-step explanation:

Number of containers required=

$18 \frac{1}{3} \div 1 \frac{5}{6}$

$\frac{55}{3} \div \frac{11}{6}$

Reciprocal

$\frac{55}{3} \times \frac{6}{11}$

$= 10$

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