Question

A large can of milk contains 18 1/3 liters of milk. If the entire milk to be poured into smaller containers, each of capacity 1 5/(6 ) liters, then find the number of containers required.

Answer 1

10

Step-by-step explanation:

Number of containers required =

$18 \frac{1}{3} \div 1 \frac{5}{6}$

$\frac{55}{3} \div \frac{11}{6}$

Reciprocal

$\frac{55}{3} \times \frac{6}{11}$

$= 10$