Question

A large concave mirror has a radius of curvature of 1.5m. A person stands 10m
in front of mirror. Where is the person's image?​

Answer 1

By using the formula with proper signs (Left of mirror is taken as negative and right is taken to be positive).

$\frac{1}{f} =\frac{1}{v}+\frac{1}{u}$

Focal length of concave mirror is taken as negative.

Focal Length = (Radius Of Curvature)/2 = 1.5/2 = 0.75

So,

f = - 0.75

u = - 10 (Persons Distance)

v = ? (Persons Image)

$\frac{-1}{0.75}= \frac{1}{v} -\frac{1}{10}$

By solving ,we get:

$\frac{1}{v} = -\frac{37}{30}$

$v=-\frac{30}{37} =0.81$

Hence:

$\huge\boxed{V=0.81m}$