Question

a large cubical tank is filled by a pipe of cross section area 56cm2 the speed of water entering the tank is 8 m/s. if the tank has a hole at its bottom then calculate the maximum height up to which the tan can be filled?

Answer 1

(i) Given,

r = 3.5 cm

h = 40 cm

By using the formula,

Volume of a cylinder = πr2h

= 22/7 × 3.5 × 3.5 × 40

= 1540 cm3

(ii) Given,

r = 2.8 m

h =15 m

By using the formula,

Volume of cylinder = πr2h

= 22/7 × 2.8 × 2.8 × 15

= 369.6 m3

Answer 2

Answer:

2.5$m^{3}$

Explanation:

Area of cross-section in $m^{2}$ = 0.56×0.56 = 0.3136 $m^{2}$

Since Height will be constant when the volume of water entering per second is equal to the volume of water exiting per second.

Threfore,

Volume of water per second = 0.3136 × 8

                                                = 2.5 $m^{3}$

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